Using the permutation formula, it is found that 5040 passwords are possible.
The order is important, as 1234 is a different password than 2134, for example, hence the permutation formula is used to solve this question.
The number of possible permutations of x elements from a set of n elements is given by:
[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]
In this problem, 4 digits are taken from a set of 10, hence:
[tex]P_{(10,4)} = \frac{10!}{6!} = 5040[/tex]
5040 passwords are possible.
You can learn more about the permutation formula at https://brainly.com/question/25925367