Answer:
20/45
6/45
Step-by-step explanation:
A bag contains 1 green, 4 red, and 5 yellow balls. Two balls are selected at random. Find P( 1 red and 1 yellow) and P(2 red).
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# of red/yellow pairs: 4*5 = 20
# of random pairs: 10C2 = 45
P(1red & 1yellow) = 20/45
# of red pairs: 4C2 = 6
# of random pairs = 45
P(2 red) = 6/45
