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What is an equation of the line that passes through the points (6,2) and
(-6,-8)? Put your answer in fully reduced form.

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Answer : y = ⅚x - 3

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Known

x1 = 6

y1 = 2

x2 = (-6)

y2 = (-8)

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Question

Equation of the line (y = mx + c)

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Way to do

#First, you find the gradient (m)

[tex]m = \frac{y2 - y1}{x2 - x1} = \frac{(( - 8) - 2)}{(( - 6) - 6)} = \frac{( - 10)}{( - 12)} = \frac{5}{6} [/tex]

#Now use the formula of equation of the line

y - y1 = m(x - x1)

y - 2 = ⅚(x - 6)

y - 2 = ⅚x - 5

y = ⅚x - 5+2

y = ⅚x - 3

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