The density of a 15.00% by mass aqueous solution of acetic acid, CH3COOH, is 1.0187g/mL. What is (a) the molarity? (b) the molality? (c) the mole fraction of each component?

Respuesta :

What is (a) the molarity?

.15 g CH3COOH / g solution ( 1 mol / 60.05 g ) (1018.7 g / L ) = 2.5 mol / L or 2.05 M


(b) the molality?

.15 g CH3COOH / g solution ( 1 mol / 60.05 g ) ( 1000 g / 1kg ) = 2.5 mol/kg or 2.5 m

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