kdiggitydawg kdiggitydawg

10-03-2021
Chemistry

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What volume of 10.0 M HCl is needed to contain 4.00 moles of HCl?

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drpelezo drpelezo

10-03-2021

Answer:

Volume of 10M HCl containing 4 moles HCl = 400 ml

Explanation:

Molarity x Volume (L) = moles

10M·V = 4 moles HCl

V = 4moles/10Molar = 4moles/10moles/Liter = 0.40L = 400ml

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