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A bucket contains 6 green tennis balls, 2 yellow tennis balls, and 7 red tennis balls. Tony removes 3 tennis balls, with replacement, from the bucket.



What is the probability that the first tennis ball is yellow, the second tennis ball is green, and the third tennis ball is red?


Answers:
A. 2/15, 0.40, 0.47

B. 0.40, 7/15, 2/15

C. 0.4, 0.13, 0.47

D. 2/15, 7/15, 0.40

Respuesta :

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Answer:

A. 2/15, 0.40, 0.47

Step-by-step explanation:

6 green tennis balls

2 yellow tennis balls

7 red tennis balls

15 total tenis balls

probability that the first tennis is a yellow ball:

[tex]\frac{2}{15}[/tex]

probability that the second tennis ball is green:

[tex]\frac{6}{15} = 0.40[/tex]

probability that the third tennis ball is red:

[tex]\frac{7}{15} = 0.4666 = 0.47[/tex]

newtbelike
I think it’s D because you count the total tennis balls together which gives u a denominator of 15. So it’s 2/15 and 7/15 and 6/15. Since 6/15 is not on option D. I made 6/15 into a decimal which was 0.4 and 0.4 is the same as 0.40. So the answer is D.

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