baobao3
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If 80,000 Joules of heat is absorbed by 210 grams of ice at 0°C, what happens to the ice?
It partially melts and stays at 0°C
It completely melts but stays at 0°C
It completely melts and has a final temperature of 11.2°C
It completely melts and has a final temperature of 22.4°C
It completely melts and has a final temperature of 33.6°C

Respuesta :

Answer:

It completely melts and has a final temperature of 22.4°C

Explanation:

(I am very bad at explaining, I am not a teacher, I am a student but I had exact same question on my test so I wanted to help.)

Okay, well to find the Heat required to melt Ice, we have to use the equation:

Q=(m·cΔT)+(m·hf)

  • Q= Heat
  • M= Mass
  • C= Specific heat
  • ΔT= Change in temperature.
  • hf= heat fusion

So we can just plug in the values into the equation and see which one adds up too 80,000. (there is probably a better way i just did it this way)

For this situation, we know that:

  • Mass=210 grams
  • Specific heat = 2.10 (I got this number 2.10 from the internet. The universal number for specific heat of ice is 2.10 J/g°C )
  • Change in temperature= 0 °C or 11.2 °C or 22.4 °C or 33.6 °C (all the answers)
  • Heat fusion=334 (universal number for heat fusion of melting ice is 334)

So we can just change the value of change and temperature and see which one equals 80,000.( I will bold the value of change in temperature.)

Q=(m·cΔT)+(m·hf)

  1. (210g)*(2.10)*(0)+(210)*(334)=70140
  2. (210g)*(2.10)*(11.2)+(210)*(334)=75079.2
  3. (210g)*(2.10)*(22.4)+(210)*(334)=80018.4
  4. (210g)*(2.10)*(33.6)+(210)*(334)=84957.6

So which one equals 80,000? Equation #3 with the temperature at 22.4 °C

So the answer would be It completely melts and has a final temperature of 22.4°C.

Hope this makes sense, again I am not a teacher I am so bad at explaining, but I did my best. ;)