Answer:
t = 2 seconds
Step-by-step explanation:
Given that,
h = -16[tex]t^{2}[/tex] + 64 t
where h and t have their usual meaning.
To determine the number of seconds required of the ball to hit the ground, differentiate the given equation with respect to t.
0 = -32 + 64
So that,
32t = 64
t = [tex]\frac{64}{32}[/tex]
t = 2
The ball will hit the ground in 2 seconds.