How do I solve this problem?

Answer:
[tex]10100[/tex]
Step-by-step explanation:
Use this formula,
[tex] \frac{n}{2} (2 {a} + d(n - 1)[/tex]
where n is the amount of even intergers, a is the starting term, d is the common difference.
[tex] \frac{100}{2} (4 + 2(99)[/tex]
[tex]50(4 + 198)[/tex]
[tex]50(202)[/tex]
[tex]10100[/tex]