Respuesta :

The equation of the ellipse with foci at (0 ±10) and vertices at (0 ±11) is [tex]\frac{x^2}{21} + \frac{y^2}{100} = 1[/tex]

How to determine the ellipse equation?

We have:

Vertices = (0, ± 11),

Foci = (0, ± 10)

The vertices and the foci are represented as:

Foci = (0, ± a)

Vertices = (0, ± c)

So, we have:

a = 10

c = 11

The equation of b is calculated using:

b² = c²- a²

So, we have:

b² = 11²- 10²

Evaluate

b² = 21

The equation of the ellipse is then represented as:

[tex]\frac{x^2}{b^2} + \frac{y^2}{a^2} = 1[/tex]

This gives

[tex]\frac{x^2}{21} + \frac{y^2}{10^2} = 1[/tex]

[tex]\frac{x^2}{21} + \frac{y^2}{100} = 1[/tex]

Hence, the equation of the ellipse is [tex]\frac{x^2}{21} + \frac{y^2}{100} = 1[/tex]

Read more about ellipse equations at:

https://brainly.com/question/10411406

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Answer:

x^2/221+Y^2/121=1

Step-by-step explanation: