Answer:
[tex]A=60\pi\ in^2[/tex]
Step-by-step explanation:
The angle made by the major arc = 210°
The sum of the measure of major arc and the minor arc is equal to 360°.
Minor arc = 360° - 210° = 150°
The radius of the circle, r = 12 inches
The area of the sector is given by :
[tex]A=\dfrac{\theta}{360}\times \pi r^2\\\\=\dfrac{150}{360}\times \pi (12)^2\\\\=60\pi\ in^2[/tex]
So, the correct option is (c) i.e. [tex]60\pi\ in^2[/tex].
