Answer:
G, 160 in^2
Step-by-step explanation:
Let us start with the general equation to find the area of this quadrilateral, which is noticably a rhombus, [tex]A=\frac{d_1d_2}{2}[/tex], where the two d represent the two diagonals of the rhombus.
Notice that the longer diagonal consists of two 10in. portions. Let's add them up to find the total length:
[tex]10+10=20[/tex]in.
Now let's find the smaller diagonal consisting of two 8 in. portions:
[tex]8+8=16[/tex]in.
Great! Let's plug in to solve for the area:
[tex]A=\frac{20*16}{2} \\A=\frac{320}{2} \\A=160[/tex]
Therefore, the area of the quadrilateral is G, 160 in^2.
I hope this helps! Let me know if you have any questions :)
