Answer:
[tex]area = length \times width \\ 9 = (x + 3)(x + 2) \\ {x}^{2} + 2x + 3x + 6 = 9 \\ {x}^{2} + 5x + 6 = 9 \\ {x}^{2} + 5x + (6 - 9) = 0 \\ {x}^{2} + 5x =3[/tex]
