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A bag of candy has 21 orange, 18 red, and 10 yellow candies. What is the probability that an orange will be drawn first and then a red (without replacement)?

Respuesta :

mhanifa

Answer:

  • 9/56

Step-by-step explanation:

There are:

  • 21 orange candies
  • 18 red candies
  • 10 yellow candies

Total number:

  • 21 + 18 + 10 = 49

Required probability is:

  • P(o, r) = 21/49*18/48 = 9/56

Total candies

  • 21+18+10
  • 49

After 1 replacement

  • 49-1=48

So

P(candy,red)

  • 21/49×18/48
  • 9/56

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