Jungkookthecookie
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In a long distance race, Michael is running at 3.8 m/s and is 75 m behind Robert, who is running at a constant velocity of 4.2 m/s. If Michael accelerates at 0.15 m/s²:

a) How much time will it take him to catch Robert?
b) How far will Michael have travelled?

Respuesta :

Answer:

t = 2.7 seconds

Explanation:

Given that,

Initial speed, u = 3.8 m/s

Final speed, v = 4.2 m/s

Acceleration of Michael, a = 0.15 m/s²

(a) Let t is the time taken by him to catch Robert. It can be calculated as follows :

[tex]a=\dfrac{v-u}{t}\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{4.2-3.8}{0.15}\\\\t=2.7\ s[/tex]

So, the time taken is 2.7 seconds.

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