Students are given the following information about a 2.0 kg, motorized toy boat on water. what net force is exerted on the boat from 4S to 8S?

The motorized toy boat experiences a net force of 0 N between 4 s and 8 s.
The motorized toy boat moves at 8 m/s (u) at 4 s and at 8 m/s (v) at 8 s. We can calculate the acceleration (a) in that period using the following kinematic expression.
[tex]a = \frac{v-u}{\Delta t} = \frac{8m/s-8m/s}{8s-4s} = 0 m/s^{2}[/tex]
The object with a mass (m) of 2.0 kg experiences an acceleration of 0 m/s². We can calculate the net force (F) in that period using Newton's second law of motion.
[tex]F = m \times a = 2.0 kg \times 0 m/s^{2} = 0 N[/tex]
The motorized toy boat experiences a net force of 0 N between 4 s and 8 s.
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