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Four circles, each with a radius of 2 inches, are
removed from a square. What is the remaining area of
the square?
(16 – 4pi) in.2
(16 – pi) in.2
(64 – 16pi) in.2
(64 – 4pi) in.?

Respuesta :

  • Area of each circle=π(2)^2=4πin^2

Area of 4circles=4(4π}+16π in^2

Hence the area if square= 4^3=64

Remaining area

[tex]\\ \sf\longmapsto (64-16\pi)in^2[/tex]

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