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Jane plans to fly from Binghamton, New York, to Springfield, Massachusetts, about 280 km due east of Binghamton. She heads due east at 280 km/h for one hour but finds herself at Keene, which is 294 km from Binghamton in a direction 17.8 degrees north of due east. What was the wind velocity

Respuesta :

Answer:

90m/h N

Explanation:

we consider janes velocity to the positive X axis so Vj=280km/s

and the final position a dot in on the graph r=294km, we find the x and y components:

294*cos(17.8)=280 X+ confirming our theory

294*sin(17.8)=90 Y+ or N and that's the winds' velocity.

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