Light intensity (I) is proportional (a) to the inverse square of distance (d) of a subject from a light
source. The relationship in intensities for subjects at different distances from the same source can
be likewise seen as a ratio or proportional relationship.
I x
A proportional relationship can be mathematically expressed as follows for light intensity (I) in
lumens when a subject is at the light source.
Lumens at current distance
Lumens at origin or source
So, if a light intensity (I) is 516 lumens at the source and 4 lumens at a specific distance from the
source, what is that distance?
Round the value to the nearest tenth if necessary. You do not need to include a label for distance.
Only the number, rounded to the tenth, will be necessary.

Respuesta :

The required distance is 11.4 rounded to the tenth

If light intensity (I) is proportional (a) to the inverse square of distance (d) of a subject from a light  source, this is expressed as:

  • l = ka/d
  • k is the variation constant

If a light intensity (I) is 516 lumens at the source and 4 lumens at a specific distance from the  source, the distance is calculated as:

l = a/d²

d² = a/l

d² = 516/4

d = √129

d = 11.4

Hence the required distance is 11.4 rounded to the tenth

Learn more on inverse variation here:https://brainly.com/question/13998680