Respuesta :
Using the binomial distribution, it is found that there is a 0.1755 = 17.55% probability that, in a random sample of 5 customers at Anita's, exactly 4 order their food to go.
For each customer, there are only two possible outcomes, either they order their food to go, or they do not. The orders of each customer are independent of other customers, hence, the binomial distribution is used to solve this question.
Binomial probability distribution
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 52% of its customers order their food to go, hence [tex]p = 0.52[/tex].
- Random sample of 5 customers, hence [tex]n = 5[/tex].
The probability that exactly 4 order their food to go is P(X = 4), hence:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 4) = C_{5,4}.(0.52)^{4}.(0.48)^{1} = 0.1755[/tex]
0.1755 = 17.55% probability that, in a random sample of 5 customers at Anita's, exactly 4 order their food to go.
To learn more about the binomial distribution, you can take a look at https://brainly.com/question/24863377
