Answer:
Another point on the graph is [tex](0;0)[/tex].
Step-by-step explanation:
To find another point on the graph, we have to find the equations of the line.
In first place, we need to calculate the slope, which definition is:
[tex]m=\frac{x_{2}-x_{1}}{y_{2}-y_{1}}[/tex]
The problem gives us the two points needed to find the slope:
[tex]m=\frac{x_{2}-x_{1}}{y_{2}-y_{1}}\\m=\frac{315-105}{3-1}=\frac{210}{2}=105[/tex]
Now, we use the slope and one point to find the equation with the point-slope formula:
[tex]y-y_{1}=m(x-x_{1})\\y-105=105(x-1)\\y=105x-105+105\\y=105x[/tex]
The independent term is missing, this means that it's zero. So, when a linear function doesn't have the independent terms, we know that the line will pass through the origin of the system, which is [tex](0;0)[/tex]
Therefore, another point on the graph is [tex](0;0)[/tex]
(The graph is attached. The slope is two high, that's why the line is almost vertical).
