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If f(x)=4x^3+16x^2-23x-15 and f(−5)=0, then find all of the zeros of f(x) algebraically.

Respuesta :

campgabe49

Answer:

4x^3+16x^2-23x-15 = (x+5)×(x+1/2)×(x-1.5)

so zeroes are at: -5, -1/2, and 1.5

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