Respuesta :

fieryanswererft

a) [tex]x^5-x^3[/tex]

[tex]x^3\left(x^2-1\right)[/tex] ........take out x³

[tex]x^3\left(x+1\right)\left(x-1\right)[/tex] ......separated (x²-1)

b) [tex]3x^2-75[/tex]

[tex]3\left(x^2-25\right)[/tex] ........took out 3.

[tex]3\left(x+5\right)\left(x-5\right)[/tex]  .......separated (x²-25)

c) [tex]3x^5y+4x^4y-5x^2y[/tex]

[tex]x^2y\left(3x^3+4x^2-5\right)[/tex] ............takeout x²y at the front.

d) [tex]81x^3-125[/tex]

[tex]81x^3-125[/tex] ......cannot be factorised much more further.

Solution:

Part - A:

To factor a polynomial, take out the factors of each term outside of the brackets. The terms of this expression are divisible by x⁴ (GCF), which can factorize completely. This will subtract 4 from the exponents.

  • => x⁵ - x³
  • => x⁴(x - 1)

Part - B:

To factor a polynomial, take out the factors of each term outside of the brackets. The terms of this expression are divisible by 3 (GCF), which can factorize completely. This will divide 3 from the terms.

  • 3x² - 75
  • 3(x² - 25)
  • 3(x + 5)(x - 5)

Part - C:

To factor a polynomial, take out the factors of each term outside of the brackets. The terms of this expression are divisible by x²y (GCF), which can factorize completely.

  • 3x⁵y + 4x⁴y - 5x²y
  • => x²y(3x³ + 4x² - 5)

Part - D:

Unfortunately, this expression can't factor with rational numbers. The expression results in 81x³ - 125.

Otras preguntas