Step-by-step explanation:
Given that:-
- Side AC measures 6 units
- Side BC measures 9.5 units
- Side AB measures 11 units
To find:-
- The cosB as a decimal rounded to the nearest hundredth
We know that,
[tex]{ \bigstar \: { \underline{ \boxed{ \cos( \theta ) \: = \sf\frac{adjecent \: side}{hypotenuse} }}}}[/tex]
Solution:
[tex] \longrightarrow \rm \cos(B) = \dfrac{BC}{AB} [/tex]
[tex]\longrightarrow \rm \cos(B) = \dfrac{9.5}{11} [/tex]
[tex]\longrightarrow \rm \cos(B) = \dfrac{95}{110} [/tex]
[tex]\longrightarrow \rm \cos(B) = 0.8 63[/tex]
[tex]\longrightarrow \rm \cos(B) \approx \: 0.9[/tex]
Therefore:
