7)
Given a series silicon diode circuit with the resistor R=2 ko ohms and an applied voltage of 10
V, what is Ipg?
A) 0.5 mA
B) 10 mA
C) 4.65 mA
D) 1.0 mA
The series circuit will have a voltage drop of about 0.7 V across the silicon diode, so the voltage drop across the 2 kΩ resistor is 10 -0.7 = 9.3 V. The current through the resistor is given by Ohm's Law:
