A 45 foot ladder is set against the side of a house so that it reaches up 27 feet. If Cooper grabs the ladder at its base and pulls it 4 feet farther from the house, how far up the side of the house will the ladder reach now? (The answer is not 23 ft.) Round to the nearest tenth of a foot.

Respuesta :

Answer:

42 feets

Step-by-step explanation:

We consider the right-angle triangle with B being the right-angle:

AB = 24 ft ; AC = 45 ft

We can use the Pythagorean theorem:

[tex]AB^{2} = AB^{2} + BC^{2} \\45^{2} = 24^{2} + BC^{2} \\BC^{2} = 2025 - 576\\BC = \sqrt{1449} = 38[/tex]

The distance between the wall and the ladder is 38 feet.

Pulling the ladder away from the wall is adding 4 feet to the distance between the wall and the ladder.

38 + 4 = 42

The ladder is now 48 feet away from the wall at its bottom.