The equation which is results from taking the square root of both sides of the provided equation is,
[tex](x+9)=\pm5\\[/tex]
A square root of a number is the value which is when multiplicand by itself gives the same value as the number posses.
Let a number is a. Then this number in the form of square root can be written as,
[tex]a=\sqrt{a}\times \sqrt{a}[/tex]
The given algebraic equation in the problem is,
[tex](x+ 9)^2 = 25[/tex]
Take the square root, in both sides,
[tex]\sqrt{(x+ 9)^2} = \sqrt{25}\\\sqrt{(x+ 9)^2} = \sqrt{5^2}[/tex]
Cancel out the square root with the square of the number as,
[tex](x+9)=\pm5\\[/tex]
Hence, the equation which is results from taking the square root of both sides of the provided equation is,
[tex](x+9)=\pm5\\[/tex]
Learn more about the square root of number here;
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