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Find the surface area of a square pyramid with base edges of 8 feet. The height of each lateral face is 15 feet. Explain or show how you got your answer.

Respuesta :

[tex]\sf\large\underline{\star Given:-}[/tex]

[tex]\rightarrow[/tex] Measure of its each edge = [tex]\sf\red{8feet.}[/tex]

[tex]\rightarrow[/tex] Height of each lateral surface (or slant height) = [tex]\sf\red{15feet.}[/tex]

[tex]\sf\large\underline{\star To\: Find:-}[/tex]

  • Surface area of the given square pyramid.

[tex]\sf\large\underline{\star Formula \:Used:-}[/tex]

[tex]\rightarrow[/tex] Surface Area of square pyramid = [tex]\sf\blue{a^2+2al}[/tex]

Where,

[tex]\sf\pink{a^2}[/tex] [tex]\sf{=\: Area \: of\: base.}[/tex]

[tex]\sf\pink{a}[/tex][tex]\sf{=\: Side \:of \:the\: base.}[/tex]

[tex]\sf\pink{l}[/tex][tex]\sf{=\: Slant \:height}[/tex]

[tex]\sf\large\underline{\star Solution:-}[/tex]

[tex]\rightarrow[/tex] Surface Area of square pyramid = [tex]\sf{a^2+2al}[/tex](putting the value of [tex]\sf{a^2}[/tex], a and l)

[tex]\rightarrow[/tex] [tex]\sf{=\: 8^2+2(8×15)}[/tex]

[tex]\rightarrow[/tex] [tex]\sf{=\: 304feet^2}[/tex]

Therefore, surface area of the given square pyramid [tex]\sf\purple{=\: 304feet^2.}[/tex]

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