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4.0 J of work are performed in stretching a spring with a spring constant of 2500 N/m. How much is the spring stretched?

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subtomex0

[tex]energy = elastic \: potential[/tex]

[tex]4 = \frac{1}{2} kx {}^{2} [/tex]

[tex]4 = \frac{1}{2} (2500)x {}^{2} [/tex]

[tex]4 = 1250x {}^{2} [/tex]

[tex]x {}^{2} = \frac{4}{1250} = 0.0032 \: meters[/tex]

[tex]x = \sqrt{0.0032} = 0.05657 \: meters[/tex]

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