Answer:
595
Step-by-step explanation:
2 positions for 35 employees.
[tex]C(n) = (\frac{n}{k}) = \frac{n!}{(k!(n-k)!)}[/tex]
Where n = 35, total number of employees and k = 2, how many spots available
[tex]\frac{35}{2} = \frac{35!}{2!(n-k)!} = \frac{35*34}{2 * 1} = 595[/tex]
