Respuesta :

Answer:

77.9 mL

Explanation:

Initial conditions

  • V₁ = ?
  • P₁ = 1 atm = 101.325 kPa
  • T₁ = 273 K

Final conditions

  • V₂ = 80.0 mL
  • P₂ = 109 kPa
  • T₂ = -12.5°C = 260.5 K

Equating Inital and Final conditions

  • V₁ = P₂V₂T₁/P₁T₂
  • V₁ = 101.325 × 80 × 273 / 109 × 260.5
  • V₁ = 2212938/28394.5
  • V₁ = 77.9 mL

Apply combine gas law

[tex]\\ \rm\Rrightarrow \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}[/tex]

[tex]\\ \rm\Rrightarrow \dfrac{101.325V_1}{273}=\dfrac{109(80)}{273-12.5}[/tex]

[tex]\\ \rm\Rrightarrow 0.37V_1=33.5[/tex]

[tex]\\ \rm\Rrightarrow V_1=90.5mL[/tex]

Otras preguntas