Answer:
[tex]log7[/tex]
Step-by-step explanation:
when adding logs, apply the log rule: [tex]\log _a\left(x\right)+\log _a\left(y\right)=\log _a\left(xy\right)[/tex]
∴ [tex]\log\left(\frac{14}{3}\right)+\log\left(\frac{11}{5}\right)=\log\left(\frac{14}{3}\cdot \frac{11}{5}\right)[/tex]
when subtracting logs, apply the log rule: [tex]\log _a\left(x\right)\:-\:\log _a\left(y\right)=\log _a\left(\frac{x}{y}\right)[/tex]
[tex]\log\left(\frac{14}{3}\cdot \frac{11}{5}\right)-\log\left(\frac{22}{15}\right)=\log\left(\frac{\frac{14}{3}\cdot \frac{11}{5}}{\frac{22}{15}}\right)\\\\=\log\left(7\right)[/tex]
