Based on the calculations, the angle between the net displacement vectors is equal to 36.9°.
Resolving the unit vectors, we have:
|a.b| = -(a.b) + (a.b)
|a.b| = -(3.6 × 1.8) + (3.6 × 1.8)
|a.b| = 12.96.
Also, the resultant vector of a and b is equal to:
|a| = √(a² + b²)
|a| = √(1.8² + 3.6²)
|a| = √(3.24 + 12.96)
|a| = √16.2
|a| = 4.025.
Similarly, the resultant vector of b is equal to 4.025.
Mathematically, the angle between the net displacement vectors is given by:
[tex]\theta = cos^{-1}( \frac{a.b}{|a||b|} )\\\\\theta = cos^{-1}( \frac{12.96}{4.025 \times 4.025} )\\\\\theta = cos^{-1}( \frac{12.96}{16.20} )\\\\\theta = cos^{-1}(0.8)[/tex]
θ = 36.9°.
Read more on unit vectors here: https://brainly.com/question/4823031
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Complete Question:
A bird flies 3.6 km due west and then 1.8 km due north. Another bird flies 1.8 km due west and 3.6 km due north. What is the angle between the net displacement vectors for the two birds?
