sitapaudel767 sitapaudel767

11-07-2022
Mathematics

contestada

sin A - sin B - sin C=-4cos A 2 .sin B 2 .sin C 2

Respuesta :

Thestudnet Thestudnet

11-07-2022

sinA+sinB+sinC

=2sin(A+B)/2cos(A-B)/2+sin C

=2sin(pi-C)/2cos(A-B)/2+2sin C/2cosC/2

=2cosC/2(cos(A-B)/2+cos(A+B)/2)

=4 cos A/2 cos B/2 cos C/2

= RHS

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