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△JKL∼△PQR

Two similar triangles. JKL and PQR. The length of JL is 28. The length of LK is unknown. The length of JK is labeled x. Angle J is labeled 35 degrees. The length of PQ is 38. The length of PR is 42. Angle P is labeled 35 degrees.



What is the value of x?

Enter your answer in the box. Round to the nearest hundredth.
x =

JKLPQR Two similar triangles JKL and PQR The length of JL is 28 The length of LK is unknown The length of JK is labeled x Angle J is labeled 35 degrees The leng class=

Respuesta :

Medunno13

Answer: 25.33

Step-by-step explanation:

Corresponding sides of similar triangles are proportional, so

[tex]\frac{x}{28}=\frac{38}{42}\\\\x={28} \left(\frac{38}{42} \right) \approx \boxed{25.33}[/tex]

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