The tension on the left wire 642N and the tension on right wire is 208N
Given that the force of scaffold is 200- N and the length of the scaffold is 18m
We need to find the tension in each wire
Tension Force is the force that is transmitted through a cable, rope, wire or string when it is pulled tight by forces acting from opposite ends
Here
∑ [tex]T_b=0[/tex]
∴ [tex]W_B(15m)+W_S(9m)-T_L(18m) = 0[/tex]
∴ [tex]T_L = \frac{W_B(15m)+W_S (9m)}{18m}\\ T_L = \frac{650(15)+200(9)}{18}\\ T_L = 642 N[/tex]
Hence the tension on the left side is 642N
∑[tex]T_a[/tex] = 0
[tex]T_R(18m)-W_B(3m)-W_S(9m)=0[/tex]
∴[tex]T_R =\frac{W_B(3m)+W_S(9m)}{18m}[/tex]
∴[tex]T_R = \frac{650(3)+200(+9)}{18}\\[/tex]
∴[tex]T_R = 208N[/tex]
Hence the tension on the right side is 208N
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