Sorry this is a bit long

b. The following reaction takes place in an acidic solution. Use the following steps to balance the equation. (5 points)
Zn(s) + NO3–(aq) Zn2+(aq) + NO(g)

i. Write the reduction and oxidation half-reactions (without electrons). (1 point)

ii. Balance the equations for atoms. Use H2O and H+ to balance O and H. (1 point)

iii. Balance the equations for charge. (1 point)

iv. Equalize charges for the two half-reactions. (1 point)

v. Add the equations and simplify to get a balanced equation. (1 point)

Question

contestada

Respuesta :

pstnonsonjoku pstnonsonjoku · Answer 1 · 2022-07-13T20:17:39+02:00

The overall balanced reaction equation is;

4Zn(s) + 10H^+(aq) + NO3^-(aq) -----> 4Zn^2+(aq) + NH4^+(aq) + 3H2O(l)

The redox reaction equation is said to be balanced when the number of electron gained is equal to the number of electrons lost.

Now;

1. Reduction and oxidation half-reactions

Zn(s) -----> Zn^2+(aq) + 2e

And

NO3^-(aq) ---->NH4^+(aq) + 3H2O(l)

2. Using the H2O and H+ to balance O and H;

4Zn(s) + 10H^+(aq) + NO3^-(aq) -----> 4Zn^2+(aq) + NH4^+(aq) + 3H2O(l)

3. Balancing the electrons lost and gained; 4Zn(s) + 10H^+(aq) + NO3^-(aq) + 8e -----> 4Zn^2+(aq) + NH4^+(aq) + 3H2O(l) + 8e

4. The overall balanced reaction equation is;

4Zn(s) + 10H^+(aq) + NO3^-(aq) -----> 4Zn^2+(aq) + NH4^+(aq) + 3H2O(l)

Learn more about redox reaction:https://brainly.com/question/13293425

#SPJ1