. Use the following reaction to determine how much of each product would be released if 42 000 kg (42 tonnes) of methyl isocyanate reacted with excess water:

The amount of 1,3-dimethyl urea produced would be 32,458 grams or 32.458 kg while that of carbon dioxide would be 16,214 grams of 16.214 kg
From the equation of the reaction, the mole ratio of methyl isocyanate with the products is 2:1 respectively.
Mole of 42,000 kg of methyl isocyanate = 42000/57 = 736.84 moles
Equivalent mole of 1,3-dimethyl urea = 736.84/2 =368.42 moles
Equivaent mole of carbon dioxide = 736.84/2 =368.42moles
Mass of 368.42 moles 1,3-dimethyl urea = 368.42 x 88.1 = 32,458 grams or 32.458 kg
Mass of 368.42 moles of carbon dioxide = 368.42 x 44.01 = 16,214 grams of 16.214 kg
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