Respuesta :
a) The wavelength λ = 0.5346 10⁻⁹ m,
b) The relationship of two length is = 1.13
Evaluating :
a) The wave-particle duality is
λ = [tex]\frac{h}{p}[/tex]
the expression for energy kinetic is :
E = p² / 2m
energy is also related to temperature
E = [tex]\frac{3}{2} kT[/tex]
we substitute ,
p = mass of the 87 RB
λ = [tex]\frac{h}{\sqrt{3mkT} }[/tex]
λ = 1.9 ×[tex]10^{-6}[/tex]
Rubidium's mass is m = 85 uma
we calculate ,
λ = 20 ×[tex]10^{-9}[/tex] × 1.9 ×[tex]10^{-6}[/tex]
λ = 0.5346 10⁻⁹ m
b) the relationship of the two lengths is
λ /0.47 nm = 0.53 / 0.47 = 1.13
de Broglie wavelength :
According to wave-particle duality, the de Broglie wavelength is a wavelength manifested in all the objects in quantum mechanics which determines the probability density of finding the object at a given point of the configuration space. The de Broglie wavelength of a particle is inversely proportional to its momentum
What is the de Broglie wavelength equation?
λ = h m v = h momentum : where 'h' is the Plank's constant. This equation relating the momentum of a particle with its wavelength is de Broglie equation and the wavelength calculated using this relation is de Broglie wavelength.
What is de Broglie's relation?
The De Broglie relation states that there is a relationship between the wavelength of an electron and its momentum, which is given by p = h/λ where h is the Planck constant and λ is the wavelength.
Learn more about de Broglie's equation :
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