The length of a rectangle is 4 ft longer than its width.
If the perimeter of the rectangle is 52 ft, find its length and width.

Respuesta :

Answer:

length=20.8

width=5.2

Step-by-step explanation:

Let the length be 4x and width be x

According to the question

perimeter=52ft

Now

perimeter of the rectangle=2(l+b)

52=2(4x+x)

52=10x

x=5.2ft

width=5.2ft

length=4x =4*5.2 =20.8ft

Answer:

  11 ft wide, 15 ft long

Step-by-step explanation:

The formula for the perimeter of a rectangle, together with the given relation between length and width, can be used to write and solve an equation for the rectangle dimensions.

Setup

Let w represent the width of the rectangle in feet. Then w+4 represents the length. The perimeter formula is ...

  P = 2(L +W)

Filling in the given values, we have ...

  52 = 2((w +4) +w)

Solution

Simplifying the equation gives ...

  52 = 4w +8

  44 = 4w . . . . . . subtract 8

  11 = w . . . . . . . . divide by 4

  w+4 = 15 . . . . . find the length

The length of the rectangle is 15 ft; the width is 11 ft.