In the figure is a right triangle ABC with AC=10cm and AB=6cm, What is the height AB (Theorem of Pythagoras)

Answer: 10 x 10 (i don't know how to type in powers) + 6 x 6 = 136
=> v136 (square root of 136) = 11.7 (3 d.p)
Step-by-step explanation:
Answer:
8cm
Step-by-step explanation:
Given-;
BC(base)=6cm
AC(hypotenuse)=10cm
To Find-:
AB(Perpendicular)=?
Solution-:
As we know that
Pythagoras Theorem=>H²=P²+B²
By using it
=>10²=P²+6²
=>100=P²+36
=>100-36=P²
=>64=P²
Therefore, the height of AB is 8cm.