Turnerrocks12 Turnerrocks12
  • 12-09-2022
  • Mathematics
contestada

Range of hx = 2r^2 + 20r +42

Respuesta :

jaisurajk jaisurajk
  • 12-09-2022

Answer: Range: hx>=-8

Step-by-step explanation:

Find the vertex first:

2r^2 + 20r +42=

2(r^2 + 20r/2 +42/2)=

2(r^2 + 10r +21)=

2(r^2 + 10r +25-4)=

2(r^2 + 5r+5r +25-4)=

2(r(r+5)+r(r+5)-4)=

2((r+5)^2-4)=

2(r+5)^2-4*2=2(r+5)^2-8   ==> Vertex: (-(5), -8) ==> (-5, -8)

-8 is when the range starts

Range: hx>=-8

Answer Link

Otras preguntas

Which term best describes the sentence
Name the tripeptide above using the three letter amino acid abbreviations separated by a hyphen (for example: gly-ala-phe).
Why did Islam spread through much of Southwest Asia during the 650s and 660s?
the ratio of pregnancy
50 points!!!! Explain the role of migration from the Middle East in each of these religions becoming part of Europe.
"And so I was glad when Charley, another veteran, arrived toward the edge of the evening, and nestled up to Henry to hear the letter read, and talked over the p
what is the solution of 7k+2=4k-10? Use one of the reasons from the box to justify each step. You may use a reason more than once.
What is paying taxes is an example of
What weapon turned the tide during the '100 years war' in favor of the English?
how much does the cricket ball weigh