C. The launch angle that would result in the same range if the launch speed is kept the same is 75⁰.
Angle of projection
The angle of projection is calculated as follows;
R = u²sin(2θ) / g
where;
- θ is the angle of projection
θ = 15⁰
sin 2θ = sin 2(15) = sin (30) = 0.5
Equivalent angle of projection
θ = 90⁰ - 15⁰ = 75⁰
sin(2θ) = sin (2 x 75⁰) = sin (150⁰) = 0.5
Thus, the launch angle that would result in the same range if the launch speed is kept the same is 75⁰.
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