Ten runners are racing. How many different ways can the runners finish first, second,
third, and fourth? (Assume there are no ties.)

Respuesta :

There are 5040 different ways can the runners finish first, second, third, and fourth place if ten runners are racing.

What is the permutation?

The permutation is defined as considered an ordered combination.

The general formula for this is:

P(n, r) = n! (n-r)!

Ten runners are racing

There are ten runners who can win first place, hence there are ten ways.

Any of the remaining 9 runners may get up to the second position in nine different ways.

Any of the remaining 8 runners may get up to the third position in eight different ways

Any of the remaining 7 runners may get up to the fourth position in seven different ways

So total number of ways = 10 × 9 × 8 × 7 = 5040

Another way 4 Out of 10 need to select where order matters

= ¹⁰P₄

= 10!/6!

= 10 × 9 × 8 × 7

= 5040

Hence, there are 5040 different ways can the runners finish first, second, third, and fourth place if ten runners are racing.

Learn more about the permutations here:

https://brainly.com/question/1216161

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