To travel a distance of 400 m the car will take a time of: 8.944 s
The formulas and procedures we will use to solve this exercise are:
- vf = √ (vi² + 2 * a * x)
- t = (2 * x)/ (vi + vf)
Where:
- vf = final velocity
- x = distance
- t = time
- vi = initial velocity
- a = acceleration
Information about the problem:
- vi = 0 m/s
- a = 10.0 m/s²
- x = 400 m
- vf =?
- t = ?
Applying the final velocity formula we have:
vf = √ (vi² + 2 * a * x)
vf = √ ((0 m/s)² + 2 * 10.0 m/s² * 400 m)
vf = √ (0 m²/s² + 8000 m²/s²)
vf = √(8000 m²/s²)
vf = 89.44 m/s
Applying the time formula we have:
t = (2 * x)/ (vi + vf)
t = (2 * 400 m)/ (0 m/s + 89.44 m/s)
t = 800 m / 89.44 m/s
t = 8.944 s
What is acceleration?
It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
Learn more about acceleration at: brainly.com/question/14344386
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