Respuesta :
Let's assume for the sake of simplicity that the third term they provided you was >3, and the twenty-fifth is >25. As a result, you put 3 as A sub-one rather than specifying that A sub-3 is 3 and A sub-25 is 25. Here's where things become tough. Set A sub-23 to 25. (why? because 1 to 23 and 3 to 25 are equally distant.
A3=3, A25=25 } A1=3, A23=25
Apply the equation An = A1 + (n-1)D.
(Read: A-sub n = A sub 1 - the nth term - D)
A23(A sub-23)= 3 Plus (23-1)
D 25 = 3 + 22D \s-3 -3
22 = 22D
D = 1
Once more, An = A1 + (n-1)D.
A3 = A1 + (3-1) X 1
3 = A1 + 2
-2 -2
A1 = 1
An = 1 + (n-1) X 1
An = 1 + 1n - 1
An = 1n + 0
So you are left with the general formula An = 1n. You can use this formula to find any term in the sequence, all you got to do is plug in (An) the number you want. In this case, plug in A sub-5 if you want to find the fifth term. You get
An = 1n
A5 = 1X5
A5 = 5
The fifth term in the sequence is 5. (it goes 1,2,3,4,,5,..)
To learn more about similar question from the given link:
brainly.com/question/2505012
#SPJ4
