The mole fraction of glycerol in this solution is 3.58%.
d = 1.037 g/ml; density of the solution
M(HOCH₂CH(OH)CH₂OH) = 92.095 g/mol; molar mass of glycerol
m= 100 ml × 1.037 g/ml
m= 103.7 g; mass of 100 ml of the solution
m(HOCH₂CH(OH)CH₂OH) = 0.16 × 103.7 g
m(HOCH₂CH(OH)CH₂OH) = 16.592 g; mass of glycerol
n(HOCH₂CH(OH)CH₂OH) = 16.592 g ÷ 92.095 g/mol
n(HOCH₂CH(OH)CH₂OH) = 0.180 mol; amount of glycerol
m(water) = 103.7 g - 16.592 g
m(water) = 87.108 g
n(water) = 87.108 g ÷ 18.0153 g/mol
n(water) = 4.835 mol; amount of water
mole fraction = 0.180 mol ÷ (0.180 mol + 4.835 mol)
mole fraction = 0.0358 = 3.58%
More about the mole fraction: brainly.com/question/14783710
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