The number of Ti atoms will be 1.9×10^25 atoms of Ti
The contribution of atom per unit cell is 2( BCC)
Edge length of unit cell is given as 2.7 ×1 inch
we will convert it in cm so it becomes 6.93 cm
we have to calculate number of Ti atoms .we have to calculate number of Ti atoms .
Density of Ti is given as 4.50g/cm³
volume of unit cell= a³
(6.93)³= 340.68 cm³
Volume of unit cell will be 340.68cm³
we can calculate mass of unit cell
density=mass/volume
4.5= mass/ 340.68
mass= 1530
no of moles can be calculated as mass/molar mass
=32.02 moles
No of atom contained by 1 mole will be
32.02 × 6.022 × 10²³
=1.92 ×10^25
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There will be 1.92× 10²⁵ Ti atoms in the final product . It is a BCC type of unit cell and by using edge length and density of the cube, the number of titanium atoms in the unit cells can be calculated.
Two atoms contribute to each unit cell ( BCC)
The unit cell's edge length is specified as 2.7 1 inch.
We'll convert it to centimeters, making it 6.93 cm.
We must determine the quantity of Ti atoms
Ti has a density of 4.50g/cm3.
cell volume equals a³
(6.93)³= 340.68 cm³
The unit cell's volume will be 340.68 cm³
We can determine a unit cell's mass.
density=mass/volume
4.5= mass/ 340.68
mass= 1530
Mass/molar mass can be used to compute the number of moles.
=32.02 moles
The number of atoms in 1 mole will be
32.02 × 6.022 × 10²³
=1.92 ×10²⁵
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