In [tex]e^{2x} =10[/tex] , x = 1., by the properties of logarithm.
Now,
In [tex]e^{2x} =10[/tex] , taking natural logarithm on both side.
=> [tex]log_e(e^{2x})=log_e(10)[/tex]
By properties of logarithm, we know that: [tex]log_b(a)^m = m(log_b(a))[/tex]
=> [tex]2x(log_e(e))=ln(10)[/tex]
Also, as [tex]log_e(e)[/tex] = 1,
=> 2x (1) = ln(10)
=> 2x = 2.302 (approx)
=> x = 1.151
Hence, In [tex]e^{2x} =10[/tex] , x = 1.151, by the properties of logarithm.
To learn more about logarithms, refer to the link: brainly.com/question/25710806
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