katgatayajairra katgatayajairra

11-02-2015
Mathematics

contestada

How do you do 4x^2+3x-10=0

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konrad509 konrad509

11-02-2015

[tex]4x^2+3x-10=0\\ 4x^2+8x-5x-10=0\\ 4x(x+2)-5(x+2)=0\\ (4x-5)(x+2)=0\\ x=\dfrac{5}{4} \vee x=-2 [/tex]

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