katgatayajairra
katgatayajairra
11-02-2015
Mathematics
contestada
How do you do 4x^2+3x-10=0
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konrad509
konrad509
11-02-2015
[tex]4x^2+3x-10=0\\ 4x^2+8x-5x-10=0\\ 4x(x+2)-5(x+2)=0\\ (4x-5)(x+2)=0\\ x=\dfrac{5}{4} \vee x=-2 [/tex]
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